Raoult’s Law Calculator
Calculate component mole fractions, partial vapor pressures, and total vapor pressure for an ideal volatile liquid mixture.
About Raoult’s law
Raoult’s law examples
These ideal mixtures demonstrate weighted pure-component vapor pressures.
| Mixture | Total vapor pressure | Calculation |
|---|---|---|
| 2 mol at 44.6 mmHg and 3 mol at 23.8 mmHg | 32.12 mmHg | Ethanol-water teaching example with mole fractions 0.4 and 0.6. |
| 1.5 mol at 53.3 kPa and 2.5 mol at 18 kPa | 31.2375 kPa | Binary benzene-toluene ideal estimate. |
| 1 mol at 80, 2 mol at 60, and 1.5 mol at 40 mmHg | 57.7778 mmHg | Three volatile components weighted by a total of 4.5 moles. |
| 2.2 mol at 38.7 kPa and 1.8 mol at 21.2 kPa | 30.825 kPa | Binary acetone-chloroform ideal estimate. |
How to use Raoult’s law
- Choose the number of volatile components in the liquid mixture.
- Select one pressure unit and obtain every pure vapor pressure at the same temperature.
- Enter the positive mole amount and pure vapor pressure for each component.
- Select Calculate Vapor Pressure to view every mole fraction and partial pressure.
- Check whether ideal-solution behavior is reasonable before applying the total pressure.
Raoult’s law FAQ
When does Raoult’s law work best?
It works best for ideal or nearly ideal liquid mixtures whose molecules have similar intermolecular interactions. Strongly associating or dissimilar compounds may require activity coefficients.
Why must pure vapor pressures use the same temperature?
Pure vapor pressure changes with temperature, and equilibrium requires one system temperature. Combining values from different temperatures gives partial pressures that do not describe one physical state.
Does the pressure-unit selector convert values?
No. It labels all entered and calculated pressures in the chosen unit. Enter every pure vapor pressure in that same unit.
Can I include a nonvolatile solute?
A nonvolatile solute can affect solvent mole fractions but contributes essentially no partial vapor pressure. For a careful calculation, account for its moles while treating its pure vapor pressure contribution appropriately.
What causes deviations from Raoult’s law?
Differences between like and unlike molecular attractions cause non-ideal behavior. Positive deviations raise vapor pressure, while negative deviations lower it relative to the ideal prediction.