Combustion Analysis Calculator

Determine elemental composition, empirical formula, and molecular formula from measured combustion products.

Combustion measurements
Enter sample, carbon dioxide, and water masses. Nitrogen, sulfur dioxide, and molar mass are optional.

About combustion analysis

Combustion analysis determines the elemental composition of a compound by measuring products formed during complete combustion. Carbon in the original sample becomes carbon dioxide, and hydrogen becomes water. If nitrogen gas or sulfur dioxide is collected, those products can also quantify nitrogen and sulfur. Oxygen in the original compound is commonly found by subtracting the masses of the measured elements from the original sample mass. The calculation begins by converting each product mass to moles. Every mole of carbon dioxide contains one mole of carbon atoms, while every mole of water contains two moles of hydrogen atoms. Every mole of nitrogen gas contains two moles of nitrogen atoms, and every mole of sulfur dioxide contains one mole of sulfur atoms. Multiplying those mole amounts by atomic masses gives the element masses used in the oxygen-by-difference step. An empirical formula expresses the smallest whole-number ratio of atoms. The element mole amounts are divided by the smallest positive amount. Ratios close to whole numbers can be rounded directly, while ratios such as 1.5 or 1.333 require multiplying all values by a small common factor. Experimental noise means ratios are rarely exact, so the calculator searches small multipliers for a close integer relationship. Poor measurements or impure samples can still produce misleading ratios. A molecular formula is a whole-number multiple of the empirical formula. When molar mass is supplied, the calculator divides it by empirical formula mass and rounds to the nearest positive integer. For glucose, combustion establishes CH2O as the empirical formula. Its empirical formula mass is about 30.026 grams per mole, and a measured molar mass near 180.156 gives a factor of six, producing C6H12O6. Complete combustion, quantitative product collection, and a pure sample are essential assumptions. Carbon monoxide, soot, retained moisture, leaks, or unmeasured heteroatoms distort the result. Oxygen by difference accumulates every mass error and is especially sensitive when oxygen is a small fraction of the sample. The optional nitrogen and sulfur fields should remain zero unless those products were actually measured by a compatible method. Use this calculator to organize stoichiometry and check laboratory work, then report formulas with precision justified by the experimental data.

Combustion analysis examples

Idealized product masses illustrate empirical and molecular formula determination.

Measured massesFormulaInterpretation
0.180156 g sample; 0.264057 g CO2; 0.108090 g H2O; molar mass 180.156CH2O; molecular C6H12O6Carbon, hydrogen, and oxygen occur in a one-to-two-to-one mole ratio.
0.160430 g sample; 0.440095 g CO2; 0.360300 g H2OCH4The product amounts correspond to one carbon for every four hydrogens.
0.600520 g sample; 0.880190 g CO2; 0.360300 g H2OCH2ODoubling all product and sample amounts leaves the empirical ratio unchanged.

How to analyze combustion data

  1. Enter the original sample mass and the masses of carbon dioxide and water collected.
  2. Add nitrogen gas or sulfur dioxide mass only when those products were measured.
  3. Optionally enter the independently measured molar mass to obtain a molecular formula.
  4. Select Analyze combustion and review the formula ratio and mass composition.

Combustion analysis FAQ

How is carbon calculated from carbon dioxide?

Moles of carbon equal moles of carbon dioxide because each molecule contains one carbon atom. Multiplying carbon moles by carbon's atomic mass gives the carbon mass.

Why are hydrogen moles twice water moles?

Each water molecule contains two hydrogen atoms. The measured water amount must therefore be multiplied by two before forming the elemental mole ratio.

How is oxygen in the sample determined?

The calculator subtracts calculated carbon, hydrogen, nitrogen, and sulfur masses from total sample mass. The remaining mass is assigned to oxygen, so unmeasured elements would invalidate that assumption.

What is the difference between empirical and molecular formulas?

The empirical formula is the simplest whole-number atom ratio. The molecular formula gives actual atom counts and is an integer multiple determined with molar mass.

Why are my ratios not exact integers?

Measured masses contain uncertainty and combustion or collection may be incomplete. Small deviations are expected, but large deviations should prompt a review of procedure and sample composition.