Combustion Analysis Calculator
Determine elemental composition, empirical formula, and molecular formula from measured combustion products.
About combustion analysis
Combustion analysis examples
Idealized product masses illustrate empirical and molecular formula determination.
| Measured masses | Formula | Interpretation |
|---|---|---|
| 0.180156 g sample; 0.264057 g CO2; 0.108090 g H2O; molar mass 180.156 | CH2O; molecular C6H12O6 | Carbon, hydrogen, and oxygen occur in a one-to-two-to-one mole ratio. |
| 0.160430 g sample; 0.440095 g CO2; 0.360300 g H2O | CH4 | The product amounts correspond to one carbon for every four hydrogens. |
| 0.600520 g sample; 0.880190 g CO2; 0.360300 g H2O | CH2O | Doubling all product and sample amounts leaves the empirical ratio unchanged. |
How to analyze combustion data
- Enter the original sample mass and the masses of carbon dioxide and water collected.
- Add nitrogen gas or sulfur dioxide mass only when those products were measured.
- Optionally enter the independently measured molar mass to obtain a molecular formula.
- Select Analyze combustion and review the formula ratio and mass composition.
Combustion analysis FAQ
How is carbon calculated from carbon dioxide?
Moles of carbon equal moles of carbon dioxide because each molecule contains one carbon atom. Multiplying carbon moles by carbon's atomic mass gives the carbon mass.
Why are hydrogen moles twice water moles?
Each water molecule contains two hydrogen atoms. The measured water amount must therefore be multiplied by two before forming the elemental mole ratio.
How is oxygen in the sample determined?
The calculator subtracts calculated carbon, hydrogen, nitrogen, and sulfur masses from total sample mass. The remaining mass is assigned to oxygen, so unmeasured elements would invalidate that assumption.
What is the difference between empirical and molecular formulas?
The empirical formula is the simplest whole-number atom ratio. The molecular formula gives actual atom counts and is an integer multiple determined with molar mass.
Why are my ratios not exact integers?
Measured masses contain uncertainty and combustion or collection may be incomplete. Small deviations are expected, but large deviations should prompt a review of procedure and sample composition.