Escape Velocity Calculator

Calculate the minimum speed needed to escape the gravity of a planet, moon, star, or other spherical celestial body.

Calculate escape velocity
Enter mass and radius in SI units to apply the classical escape speed equation.

About escape velocity

Escape velocity is the minimum initial speed an object needs to move away from a gravitating body without further propulsion and without eventually falling back. This calculator uses the classical spherical-body equation v = sqrt(2GM divided by r), where G is the universal gravitational constant, M is the mass of the celestial body, and r is the distance from its center. When launch begins at the surface, r is the body's mean radius. The result assumes the object starts with kinetic energy and coasts outward while gravity converts that kinetic energy into gravitational potential energy. The equation follows from conservation of mechanical energy. At the threshold escape speed, the traveling object's speed approaches zero only at an infinite distance, so its total specific energy is zero. The mass of the escaping spacecraft cancels from the derivation. A small probe and a large spacecraft therefore have the same ideal escape velocity from the same location, although the larger craft requires proportionally more energy and fuel in practice. Real launches are more complicated than this ideal model. Atmospheric drag, engine efficiency, changing thrust, planetary rotation, and gravity losses all affect the required launch profile. Rockets do not normally receive escape speed instantaneously; they build velocity over time and may first enter a parking orbit. The displayed value is best understood as an energy threshold rather than a complete mission-planning number. It also ignores the gravity of nearby bodies and assumes a non-rotating, spherically symmetric source. Mass must be entered in kilograms and radius in meters. If the starting point is above the surface, use the body's radius plus that altitude. Increasing mass raises escape velocity because the gravitational field is stronger. Increasing the starting radius lowers it because the object begins higher in the gravitational potential. Escape velocity is sqrt(2) times circular orbital velocity at the same radius under the same two-body assumptions. The calculator is useful for comparing planets and moons, checking astronomy coursework, and estimating the scale of spaceflight requirements. Earth's surface value is about 11.2 km/s, the Moon's is about 2.38 km/s, and Mars lies between them at roughly 5.03 km/s. Compact stars produce far greater values, but classical Newtonian calculations become inaccurate near extremely compact objects where relativistic gravity is important.

Escape velocity examples

These ideal surface values use mean mass and radius data.

Celestial bodyEscape velocityInterpretation
Earth: 5.972e24 kg, 6,371 km11.186 km/sIdeal speed from mean sea-level radius.
Moon: 7.342e22 kg, 1,737.4 km2.376 km/sLow gravity makes lunar escape much easier.
Mars: 6.4171e23 kg, 3,389.5 km5.027 km/sUses Mars's mean planetary radius.

How to calculate escape velocity

  1. Enter the celestial body's mass in kilograms, using scientific notation for very large values if convenient.
  2. Enter the distance from the body's center in meters; for a surface launch, use its mean radius.
  3. Select Calculate Escape Velocity to evaluate the classical gravitational equation.
  4. Read the result in meters per second and kilometers per second, then account separately for real mission losses.

Escape velocity FAQ

Does the escaping object's mass affect escape velocity?

No, its mass cancels when kinetic and gravitational potential energy are equated. A heavier object needs more total energy, but the ideal threshold speed is unchanged.

Why do rockets not launch instantly at 11.2 km/s?

Rockets add speed progressively while climbing and can follow an orbital trajectory before departing Earth. Atmospheric drag, gravity losses, and propulsion efficiency also make the practical maneuver different from the ideal calculation.

Is escape velocity the same at every altitude?

No, it decreases as distance from the body's center increases. Add altitude to the mean radius when calculating from a point above the surface.

How is escape velocity related to orbital velocity?

At a given radius, ideal escape velocity is sqrt(2) times the circular orbital velocity. Both relationships assume a spherical body and a two-body Newtonian model.

Can this equation be used for black holes?

Not reliably near a black hole or another extremely compact object. General relativity is required when spacetime curvature is strong and the classical result approaches the speed of light.