Orbital Velocity Calculator

Calculate circular orbital speed, orbital period, and escape velocity from a central body's mass and orbital radius.

Calculate orbital motion
Enter mass in kilograms and distance from the body's center in metres.

About orbital velocity

Orbital velocity is the sideways speed an object needs to remain in a circular path around a much more massive central body. Gravity continually pulls the orbiting object inward, while its forward motion keeps it falling around the body rather than directly toward the surface. This calculator uses the standard two-body approximation: orbital velocity equals the square root of the gravitational constant multiplied by central mass and divided by orbital radius. The radius must be measured from the center of the central body, not from its surface. The calculator also finds orbital period, the time needed to complete one revolution. The period follows from the circumference of the orbit divided by orbital speed and is equivalent to Kepler's circular-orbit equation. Escape velocity is included for comparison. It is the minimum ideal speed at the same radius that gives an object enough kinetic energy to escape the central body's gravity without further propulsion. At any given radius, escape velocity is the square root of two times circular orbital velocity. Use SI units for consistent results: kilograms for central mass and metres for radius. For a satellite above Earth, add Earth's mean radius, approximately 6,371,000 metres, to the altitude above sea level. For example, a spacecraft 400 kilometres above Earth has an orbital radius near 6,771 kilometres. The calculation assumes a spherical central body, a circular orbit, negligible satellite mass, and no atmospheric drag. Real spacecraft may have elliptical orbits, experience perturbations from other bodies, and require corrections for an uneven gravity field. Orbital velocity decreases as orbital radius increases, while orbital period grows rapidly. This explains why low Earth orbit satellites travel several kilometres each second and circle Earth in roughly ninety minutes, whereas geostationary satellites move more slowly and take one sidereal day. The same formulas apply to moons, planets, and artificial satellites whenever one mass dominates the system. Engineers can use these results for quick mission estimates, students can check orbital mechanics exercises, and astronomy learners can compare motion around different planets or stars. For precision mission design, use complete ephemerides and numerical trajectory models rather than this idealized circular calculation.

Orbital velocity examples

Representative circular orbits illustrate how mass and radius control speed and period.

InputsApproximate resultContext
Earth, radius 6,771 km7.673 km/s; 92.4 minA satellite about 400 km above Earth's surface.
Earth, radius 42,164 km3.075 km/s; 23.93 hThe geostationary orbital radius.
Earth, radius 384,400 km1.018 km/s; 27.45 daysA circular approximation of the Moon's orbit.

How to calculate orbital velocity

  1. Enter the mass of the central planet, moon, or star in kilograms.
  2. Enter the orbital radius measured from the center of that body in metres.
  3. Select Calculate Orbit to compute circular speed, period, and escape speed.
  4. Compare the results or reset the fields to evaluate another orbit.

Orbital velocity FAQ

Is orbital radius the same as altitude?

No. Orbital radius is measured from the body's center, while altitude is measured from its surface. Add the body's radius to altitude before using this calculator.

Why does a higher orbit move more slowly?

Gravity is weaker farther from the central body, so a lower circular speed balances the inward acceleration. The larger path still takes longer to complete.

What assumptions does the formula make?

It assumes a circular orbit, a spherical central mass, and an orbiting object whose mass is negligible. Atmospheric drag and gravitational perturbations are ignored.

How is escape velocity related to orbital velocity?

At the same radius, ideal escape velocity is the square root of two times circular orbital velocity. It is about 41.4 percent greater.

Can I use this for planets orbiting a star?

Yes, when the star's mass greatly exceeds the planet's mass and a circular approximation is suitable. Use the star's mass and the planet's center-to-center orbital radius.