Bond Order Calculator
Calculate molecular orbital bond order from bonding and antibonding electron counts.
About molecular orbital bond order
Bond order examples
| Electron counts | Bond order | Interpretation |
|---|---|---|
| O₂: 10 bonding, 6 antibonding | 2 | The net interaction corresponds to a double bond. |
| N₂: 10 bonding, 4 antibonding | 3 | The net interaction corresponds to a strong triple bond. |
| He₂: 2 bonding, 2 antibonding | 0 | Equal stabilization and destabilization predict no net bond. |
| O₂ positive ion: 10 bonding, 5 antibonding | 2.5 | Removing one antibonding electron raises bond order by one half. |
How to calculate bond order
- Draw or obtain the correct molecular orbital diagram for the species.
- Count all electrons occupying bonding molecular orbitals.
- Count all electrons occupying antibonding molecular orbitals.
- Enter both totals and select Calculate bond order.
Bond order calculator FAQ
What does a higher bond order mean?
A higher bond order usually indicates a stronger and shorter bond between the atoms. Comparisons are most meaningful for closely related species with similar bonding frameworks.
Can bond order be fractional?
Yes, molecular ions and delocalized molecules can have fractional bond orders. Adding or removing one electron from a bonding or antibonding orbital changes molecular orbital bond order by one half.
What does a bond order of zero mean?
It means bonding and antibonding contributions cancel in the simple molecular orbital count. The selected electron configuration therefore does not predict a stable net bond.
Do nonbonding electrons count?
No, nonbonding orbitals are omitted from this formula because they provide neither net bonding nor net antibonding contribution. Only electrons in explicitly bonding and antibonding orbitals are counted.
Is this the same as Lewis structure bond order?
The ideas are related but the calculation here specifically uses molecular orbital occupancy. Resonance-based Lewis bond orders are often averages and are derived differently.