Equilibrium Constant Calculator
Calculate Kc or Kp from equilibrium activity terms and convert between concentration and pressure constants at a chosen temperature.
About equilibrium constants
Equilibrium constant examples
These examples show direct activity ratios and ideal-gas conversions.
| Inputs | Result | Interpretation |
|---|---|---|
| Product term 0.36; reactant term 0.12 | Kc = 3 | Products are favored relative to the supplied reactant term. |
| Kp 2.5; 300 K; delta n = 1 | Kc = 0.10155542 | Divide Kp by RT because one additional mole of gas is produced. |
| Kc 0.5; 298.15 K; delta n = 0 | Kp = 0.5 | The constants are numerically equal when gaseous mole counts do not change. |
How to use the equilibrium constant calculator
- Choose whether to calculate Kc or Kp from activity terms, or convert between the two constants.
- For a direct calculation, enter the complete product activity term and reactant activity term from the balanced equation.
- For a conversion, enter the known constant, absolute temperature in kelvin, and gaseous stoichiometric change delta n.
- Select Calculate equilibrium constant and interpret the displayed dimensionless value.
Equilibrium constant FAQ
What does a large equilibrium constant mean?
A large K means the equilibrium mixture is product-favored under the stated standard conditions. It does not reveal how quickly equilibrium will be reached.
Are solids included in Kc?
Pure solids and pure liquids are omitted because their activities are treated as one. Dissolved and gaseous species remain in the expression when their activities can vary.
When are Kp and Kc equal?
They have the same numerical value when delta n for gaseous species is zero. They are also related through the standard-state convention, so units must be handled consistently.
Does a catalyst change the equilibrium constant?
No, a catalyst accelerates both forward and reverse processes and helps the system reach equilibrium sooner. It does not change the equilibrium composition or K.
Why must temperature be in kelvin?
The ideal-gas factor RT requires an absolute thermodynamic temperature. Celsius values would make the conversion physically incorrect.