Bertrand's Box Paradox Calculator
Explore conditional probability through the famous three-box coin puzzle.
About Bertrand's Box Paradox
Box Paradox Examples
Each result conditions on drawing a gold coin first.
| Box Counts (GG, GS, SS) | Probability | Reasoning |
|---|---|---|
| 1, 1, 1 | 66.67% | Two of three possible gold faces are in the Gold-Gold box. |
| 2, 1, 3 | 80.00% | Four of five possible gold faces are in Gold-Gold boxes. |
| 1, 2, 0 | 50.00% | Two Gold-Gold faces and two mixed-box gold faces are equally balanced. |
How to Use the Calculator
- Enter the number of Gold-Gold, Gold-Silver, and Silver-Silver boxes.
- Confirm that box selection and coin selection are equally likely.
- Select Calculate Conditional Probability to condition on a gold observation.
- Compare favorable Gold-Gold faces with all faces capable of showing gold.
Frequently Asked Questions
Why is the classic answer not one-half?
The two remaining box types are not equally likely after gold is observed. The Gold-Gold box offers twice as many ways to produce that observation.
Why do Silver-Silver boxes not affect the result?
A Silver-Silver box cannot produce the given gold observation, so its conditional weight becomes zero. It does affect probabilities before the coin is observed.
How does Bayes' theorem apply?
Bayes' theorem reweights each possible box by how likely it was to produce a gold coin. The calculator performs that reweighting by counting gold-producing faces.
What assumptions does the calculation use?
Every box is assumed equally likely to be chosen, and each coin in a box is equally likely to be drawn. Biased selection would require weighted probabilities instead of simple counts.
Can I model more than three boxes?
Yes, enter any nonnegative whole-number count for each box type. The same conditional formula applies when box types are duplicated.