Pump Horsepower Calculator

Calculate hydraulic horsepower and required brake horsepower from flow, head, fluid density, and pump efficiency.

Hydraulic Power Calculation
Enter U.S. gallons per minute, total dynamic head in feet, specific gravity, and overall pump efficiency.

About Pump Horsepower

Pump horsepower describes the rate of work needed to move a liquid through a piping system. This calculator uses the standard U.S. customary pump equation, combining flow rate in gallons per minute, total dynamic head in feet, fluid specific gravity, and pump efficiency. The first three quantities determine hydraulic horsepower, which is the useful power transferred to the liquid. Dividing that value by decimal efficiency estimates brake horsepower, the mechanical power that must reach the pump shaft. Total dynamic head is more than the vertical lift between two points. It normally includes static elevation, pressure head, and friction losses through pipe, fittings, valves, filters, and equipment. A reliable system estimate therefore depends on a realistic head calculation at the intended operating flow. Specific gravity compares the pumped liquid's density with water. Water near ordinary temperatures has a specific gravity close to 1.0, while oils are often lower and concentrated solutions can be higher. Because a denser liquid requires more power at the same flow and head, specific gravity scales horsepower directly. Efficiency accounts for losses inside the pump and drive. If a pump transfers 80 percent of its shaft power to the fluid, its decimal efficiency is 0.80. The required shaft horsepower is consequently greater than hydraulic horsepower. Use the efficiency at the expected duty point from the manufacturer's performance curve rather than a generic peak value. Motor efficiency and service factor may require additional consideration when selecting the electrical motor, because this result describes pump shaft demand rather than electrical input. The result is a sizing estimate, not a substitute for a complete pump selection. Engineers generally choose a motor with adequate margin, then confirm that the operating point lies near the pump's best efficiency region and that net positive suction head requirements are satisfied. Fluid viscosity, temperature, solids, transient conditions, and future system changes can alter actual demand. For critical installations, compare this calculation with vendor curves and applicable design standards before purchasing equipment.

Pump Horsepower Examples

These examples use the same U.S. customary equation as the calculator.

InputsBrake horsepowerApplication
100 gpm, 50 ft, SG 1.00, 80%1.578 hpSmall water circulation pump
250 gpm, 120 ft, SG 1.10, 75%11.111 hpDense glycol solution
500 gpm, 80 ft, SG 0.85, 70%12.266 hpLight hydrocarbon transfer

How to Calculate Pump Horsepower

  1. Enter the required flow rate in U.S. gallons per minute.
  2. Enter total dynamic head, including elevation, pressure, and friction losses.
  3. Provide the liquid specific gravity and the pump efficiency at the duty point.
  4. Select Calculate Pump Horsepower and use the brake horsepower result for preliminary sizing.

Frequently Asked Questions

What is the difference between hydraulic and brake horsepower?

Hydraulic horsepower is useful power delivered to the liquid. Brake horsepower is shaft power supplied to the pump, so it is higher whenever efficiency is below 100 percent.

What should I include in total head?

Include static elevation, required pressure difference, and losses through pipe, fittings, valves, and equipment. Calculate those losses at the design flow because friction changes with flow rate.

Why does specific gravity affect pump power?

Specific gravity represents liquid density relative to water. A heavier liquid requires proportionally more power to produce the same volumetric flow and head.

Which pump efficiency should I use?

Use the efficiency shown on the manufacturer's curve at the expected operating point. Do not automatically use peak efficiency, because the actual duty point may be away from that peak.

Does this result give electrical input power?

No, the result estimates mechanical power at the pump shaft. Electrical input also depends on motor and drive efficiency, so account for those losses when evaluating energy use.