Elongation Calculator

Calculate tensile elongation, engineering strain, and stress from force, area, length, and Young's modulus.

Calculate material deformation
Use the linear-elastic Hooke's law relationship for a uniform member under axial tension.

About tensile elongation

Elongation is the increase in a material's length when an axial tensile force pulls on it. Engineers use this value to predict whether cables, rods, bolts, and structural members will stretch an acceptable amount under service loads. For a straight member with a uniform cross section that remains within its linear-elastic range, elongation is calculated as force times original length divided by cross-sectional area times Young's modulus. The calculator evaluates that relationship in SI units and also reports stress, strain, and final length. Tensile stress describes applied force distributed over the original cross-sectional area. Its SI unit is the pascal, equivalent to one newton per square meter. Engineering strain is the elongation divided by original length and has no physical unit. In the linear-elastic region, Hooke's law says that stress equals Young's modulus times strain. Young's modulus therefore measures stiffness: steel's modulus is around 200 gigapascals, aluminum's is near 69 to 70 gigapascals, and flexible polymers can be many orders of magnitude lower. The calculation assumes a centered axial load, constant area, homogeneous material, small deformation, and a temperature that does not independently change the member's length. It does not account for yielding, necking, stress concentrations, creep, fatigue, joint slip, or geometric nonlinearity. If calculated stress exceeds the material's proportional limit or yield strength, the simple elastic result should not be treated as the permanent deformation. Design work should also apply the relevant safety factor and code requirements. Accurate inputs matter because area and modulus appear in the denominator. For a circular wire, use the area based on diameter rather than entering the diameter itself. Convert square millimeters to square meters before entry; one square millimeter is 10^-6 square meters. Use the effective load-bearing area where threads, holes, corrosion, or strands reduce the section. The reported final length is original length plus elastic elongation. These outputs make the tool useful for quick checks of tie rods, suspension cables, laboratory tensile specimens, machine elements, and classroom Hooke's law exercises.

Elongation examples

The values below use the linear-elastic axial deformation equation.

Load and memberElongationInterpretation
5,000 N; 0.000314 m²; 10 m; 200 GPa0.000796 mSteel cable under load
2,000 N; 0.0001 m²; 2 m; 70 GPa0.000571 mAluminum rod in tension
500 N; 0.000025 m²; 5 m; 110 GPa0.000909 mCopper wire extension
10 N; 0.000001 m²; 0.1 m; 1 MPa1 mMathematical result is outside small-strain assumptions

How to calculate elongation

  1. Enter the axial tensile force in newtons.
  2. Enter the member's load-bearing cross-sectional area in square meters.
  3. Provide the original length in meters and Young's modulus in pascals.
  4. Select Calculate Elongation and compare the resulting stress with the material's elastic limit.

Elongation calculator FAQ

What is the formula for elastic elongation?

For a uniform axially loaded member, elongation equals force times length divided by area times Young's modulus. This formula follows from engineering stress, engineering strain, and linear Hooke's law.

Is elongation the same as strain?

No, elongation is an absolute change in length and is measured here in meters. Strain is elongation divided by original length, so it is a dimensionless ratio.

Can this calculator predict permanent stretch?

It predicts recoverable deformation only while the material behaves linearly and elastically. Plastic deformation requires a material-specific stress-strain curve or another constitutive model.

Which area should I enter for a round rod?

Use the circular cross-sectional area calculated from the rod's diameter. Do not enter diameter in the area field, and account for any reduced or threaded section that carries the load.

Why does a longer member stretch more?

Each small segment undergoes approximately the same strain under uniform stress. A longer member contains more such segments, so their individual extensions add to a larger total elongation.