Gibbs Free Energy Calculator
Calculate reaction Gibbs free energy from enthalpy and entropy or from an equilibrium constant, then assess thermodynamic spontaneity.
About Gibbs free energy
Gibbs free energy examples
Examples demonstrate both supported thermodynamic routes.
| Inputs | Result | Interpretation |
|---|---|---|
| ΔH = -100 kJ/mol; ΔS = -200 J/mol·K; T = 298 K | ΔG = -40.4 kJ/mol | The forward process is favorable at this temperature. |
| K = 10; T = 298.15 K | ΔG° ≈ -5.708 kJ/mol | A product-favored equilibrium gives a negative standard Gibbs energy. |
| ΔH = 25 kJ/mol; ΔS = 100 J/mol·K; T = 350 K | ΔG = -10 kJ/mol | The favorable entropy term outweighs positive enthalpy at 350 K. |
How to use the Gibbs free energy calculator
- Choose the enthalpy and entropy method or the equilibrium constant method.
- Enter the requested values and provide absolute temperature in kelvin.
- Check that enthalpy is in kilojoules and entropy is in joules per mole kelvin.
- Select Calculate Gibbs free energy and use the sign to assess thermodynamic direction.
Gibbs free energy FAQ
Does negative delta G mean a reaction is fast?
No, delta G describes thermodynamic favorability rather than reaction rate. A large activation barrier can keep a favorable reaction extremely slow.
Why must temperature be in kelvin?
Both thermodynamic equations require an absolute temperature scale. Substituting Celsius directly gives a physically meaningless energy term.
What happens when delta G equals zero?
The system has no net thermodynamic driving force and is at equilibrium for the stated composition. Forward and reverse microscopic processes may still continue at equal rates.
What is the difference between delta G and standard delta G?
Standard delta G refers to defined standard states, while actual delta G also depends on the current reaction quotient. The equilibrium-constant equation returns the standard value at the selected temperature.
Can a catalyst change delta G?
A catalyst changes the kinetic pathway and activation energy but not the initial and final thermodynamic states. It therefore does not alter delta G or the equilibrium constant.