Central Limit Theorem Calculator

Estimate the probability that a sample mean falls within a range using the normal sampling distribution.

Sample mean probability
Enter population parameters, sample size, and lower and upper sample-mean bounds.

About the central limit theorem

The central limit theorem explains why normal distributions appear throughout statistical inference. When independent observations are drawn from a population with a finite mean and variance, the distribution of their sample mean becomes approximately normal as the sample size grows. This can happen even when the underlying population is skewed or otherwise non-normal. The sampling distribution is centered at the population mean and has a standard deviation called the standard error. For a population mean μ, population standard deviation σ, and sample size n, the standard error of the mean is σ/√n. Increasing the sample size therefore makes sample means cluster more tightly around μ. To find the probability that a sample mean lies between lower and upper bounds, convert each bound to a z-score using z = (x̄ - μ)/(σ/√n). The desired probability is the area under the standard normal curve between those two z-scores. Suppose a population has mean 100 and standard deviation 15. For samples of 36 observations, the standard error is 15/6 = 2.5. Bounds of 95 and 105 correspond to z-scores of -2 and 2. The standard normal distribution places about 95.45 percent of its area between those points, so approximately 95.45 percent of repeated sample means would fall in that interval under the model. The theorem is asymptotic, not a universal rule that every sample of 30 is automatically normal. How quickly the approximation improves depends on the population's shape. A nearly normal population may need only a small sample, while a severely skewed or heavy-tailed population may require much more data. Dependence between observations, infinite variance, strong selection bias, or an unrepresentative sampling process can invalidate the simple calculation. If the source population itself is normal, however, the sample mean is exactly normal for every positive sample size. This calculator assumes the population standard deviation is known. In practical inference it is often estimated from sample data; confidence intervals and tests may then use a t distribution, especially for small samples. The displayed probability describes repeated random samples under the supplied population model, not the probability that a fixed unknown parameter lies in the entered range. Use the tool for sampling-distribution exercises, quality-control planning, survey estimates, and probability checks, while matching its assumptions to the design that produced the observations.

Central limit theorem examples

Population and rangeProbabilityCalculation
μ=100, σ=15, n=36, 95 to 10595.4500%SE=2.5 and the bounds are z=-2 and z=2.
μ=50, σ=10, n=25, 48 to 5268.2689%SE=2 and the bounds are z=-1 and z=1.
μ=20, σ=4, n=16, 19 to 2168.2689%SE=1, again producing the central one-standard-error interval.
μ=500, σ=60, n=100, 488 to 51295.4500%SE=6 and each bound is two standard errors from the mean.

How to calculate a sample mean probability

  1. Enter the population mean and known population standard deviation.
  2. Enter the number of independent observations in each sample.
  3. Enter the lower and upper bounds for the sample mean.
  4. Click Calculate Probability to view the standard error, z-scores, and normal probability.

Central limit theorem FAQ

What is the standard error of the mean?

It is the standard deviation of the sampling distribution of the mean. With known population standard deviation, it equals σ divided by the square root of n.

Does the population have to be normally distributed?

Not necessarily, because the sampling distribution of the mean approaches normality as sample size grows under the theorem's conditions. More skewed or heavy-tailed populations generally require larger samples.

Is a sample size of 30 always enough?

No, 30 is only a common rule of thumb. The needed size depends on population shape, dependence, outliers, and the accuracy required.

Why does a larger sample size reduce standard error?

Averaging more independent observations cancels more random variation. Mathematically, standard error decreases in proportion to one divided by the square root of sample size.

When should I use a t distribution instead?

Use a t procedure when the population standard deviation is unknown and estimated from the same sample, especially for small samples. The correct choice also depends on the inferential question and assumptions.