Thermal Efficiency Calculator

Find the percentage of heat input converted into useful work by a heat engine.

Calculate thermal efficiency
Enter heat input and useful work output in the same energy unit.

About thermal efficiency

Thermal efficiency describes the fraction of supplied heat energy that a heat engine converts into useful work. This calculator uses η = Wout/Qin × 100%, where η is efficiency as a percentage, Wout is net useful work output, and Qin is heat absorbed from the hot source. The remaining energy is rejected as heat: Qout = Qin - Wout. Heat and work must use the same unit, such as joules, kilojoules, or kilowatt-hours, because efficiency is a dimensionless ratio. A heat engine operates cyclically between hot and cold surroundings. It cannot convert all absorbed heat to work while completing a cycle; some energy must be discharged to a lower-temperature sink. This is a consequence of the second law of thermodynamics, not merely imperfect construction. Real engines lose additional useful energy through friction, combustion irreversibility, finite temperature differences, pumping, exhaust, cooling, and auxiliary equipment. Consequently, measured efficiency is always below the relevant ideal limit. Thermal efficiency may be reported on different boundaries and fuel bases. Gross indicated efficiency, brake thermal efficiency, and overall plant efficiency do not necessarily include the same losses. Fuel calculations may use higher or lower heating value, which changes the denominator. Compare systems only when heat input, useful output, operating state, and measurement boundary are defined consistently. For a device producing electrical power, integrate power over the same interval used to determine fuel heat input, or compare steady powers when storage is negligible. The ideal maximum for an engine operating between two constant-temperature reservoirs is the Carnot efficiency, 1 - Tc/Th, with both absolute temperatures in kelvins. The simple energy-ratio calculator does not require temperatures and does not claim Carnot performance. Instead, it evaluates observed or specified energy flows. A result above 100 percent signals inconsistent inputs, mismatched units, an omitted energy source, or an accounting-boundary problem, so this interface rejects work greater than heat input. Use this result for classroom thermodynamics, first-pass engine comparisons, and energy-balance checks. Detailed system assessment should include uncertainty, transient operation, fuel composition, parasitic loads, heat recovery, and the exact definition of useful output. Efficiency is not the same as power: a highly efficient engine can have low power, while a powerful engine can waste a large share of its input energy.

Thermal efficiency examples

Work and heat are compared over the same operating interval.

Energy inputsEfficiencyRejected heat
Qin 1000 J, Wout 400 J40%600 J
Qin 2500 J, Wout 875 J35%1625 J
Qin 8 MJ, Wout 3 MJ37.5%5 MJ

How to calculate thermal efficiency

  1. Determine total heat energy supplied to the engine.
  2. Determine net useful work over the same interval.
  3. Convert both quantities to the same energy unit.
  4. Select Calculate efficiency and review efficiency and rejected heat.

Frequently asked questions

Can thermal efficiency exceed 100 percent?

No, an isolated heat-engine energy balance cannot produce more work than supplied energy. A larger result indicates inconsistent units or an omitted input.

Do the inputs have to be in joules?

Any common energy unit works when both inputs use that same unit. The rejected-heat label assumes joules because the displayed fields request joules.

What is rejected heat?

Rejected heat is the input energy not converted to useful work in this balance. It leaves through cooling, exhaust, and other thermal paths.

Is thermal efficiency the same as mechanical efficiency?

No, thermal efficiency compares work with heat input. Mechanical efficiency usually compares shaft output with internally developed mechanical work.

Why can no heat engine be 100 percent efficient?

A cyclic heat engine must reject entropy and heat to a colder sink. Real irreversibilities reduce efficiency even further below the ideal limit.