Stefan-Boltzmann Law Calculator
Find thermal radiation heat flux, power, and energy from an ideal or gray surface.
About the Stefan-Boltzmann law
Radiation examples
The following cases demonstrate the strong fourth-power temperature effect.
| Inputs | Results | Interpretation |
|---|---|---|
| 300 K, emissivity 1, 2 m², 10 s | 459.3 W/m²; 9,186 J | An ideal room-temperature blackbody. |
| 1,000 K, emissivity 0.5, 1 m², 2 s | 28,351.9 W/m²; 56,703.7 J | A hot gray surface radiates intensely. |
| 500 K, emissivity 0.8, 0.5 m², 60 s | 2,835.2 W/m²; 85,055.6 J | A smaller warm surface over one minute. |
How to use the radiation calculator
- Convert the surface temperature to kelvins and enter it.
- Enter a material emissivity from zero to one.
- Enter the radiating surface area and elapsed time.
- Select Calculate radiation and compare flux, power, and energy.
Stefan-Boltzmann law FAQ
Why must temperature be in kelvins?
The law uses absolute temperature raised to the fourth power. Celsius and Fahrenheit have offset zeros and therefore produce incorrect results if entered directly.
What does emissivity mean?
Emissivity compares a real surface's emission with an ideal blackbody at the same temperature. It ranges from zero to one in this gray-body model.
Is this net heat transfer?
No, the result is gross radiation emitted by the surface. Net exchange requires accounting for radiation received from the surroundings.
Why does temperature change the answer so much?
Radiant flux scales with the fourth power of absolute temperature. Even a modest temperature increase can therefore cause a large rise in emission.
Does surface color determine emissivity?
Visible color alone is not a reliable guide to thermal infrared emissivity. Material, finish, oxidation, wavelength, and temperature all matter.