Calculate average shear stress from force, resisting area, and single- or double-shear loading.
Shear force and area
Enter force in newtons and the area of one shear plane in square millimetres.
About shear stress
Shear stress measures tangential force distributed over a resisting area. It acts parallel to a cross section rather than perpendicular to it. For a uniformly loaded connection or material section, average shear stress is tau = F / A, where F is shear force and A is the area carrying that force. This calculator uses newtons and square millimetres, so the numerical result is newtons per square millimetre, exactly equivalent to megapascals.
Many pins, bolts, rivets, and clevis connections can be described as either single shear or double shear. In single shear, one section of the fastener resists the load. In double shear, two comparable sections share it, so the total resisting area is twice the area of one plane. The calculator divides force by the entered area and by the selected number of planes. This distinction can halve the average stress for the same force and fastener diameter.
Average stress is a useful first design check, but actual stress is not perfectly uniform. Load transfer near contact surfaces creates bearing pressure and localized peaks. Holes, notches, threads, gaps, and eccentric loading introduce concentrations or bending. A complete connection design may need checks for fastener shear, plate bearing, tear-out, net-section tension, bending, fatigue, and deformation in addition to the average value shown here.
Area must correspond to the physical plane being cut by the load. For a round pin in single shear, the nominal area is pi times diameter squared divided by four. In double shear, enter that one-plane circular area and select double shear; do not manually double the area as well. For rectangular sections, use width multiplied by thickness when that rectangle is the resisting plane.
Material strength is not an input because the calculator reports demand rather than capacity. Compare the result with an allowable shear stress or a design resistance established by the governing material specification and code. Safety factors, load factors, temperature effects, corrosion allowance, and fatigue requirements belong in that comparison.
The tool is suitable for coursework, preliminary sizing, and quick verification of ideal connections. It does not replace finite element analysis or code-based design where stress distribution is complex. Confirm units carefully: an area entered in square metres would need conversion to square millimetres before use, and one square metre equals one million square millimetres.
Shear stress examples
Load case
Average stress
Interpretation
10,000 N over 500 mm², single shear
20 MPa
One plane carries the complete force.
10,000 N over 250 mm², double shear
20 MPa
Two 250 mm² planes share the force.
2,500 N over 125 mm², single shear
20 MPa
Stress is force divided by area.
How to calculate shear stress
Enter the total shear force in newtons.
Enter the resisting area of one shear plane in square millimetres.
Choose single shear or double shear to match the connection.
Select Calculate Shear Stress and compare the result with the allowable value.
Shear stress FAQ
What is the basic shear stress formula?
Average shear stress is force divided by resisting area. For multiple equal shear planes, divide by the combined area of all planes.
What is the difference between single and double shear?
Single shear has one failure plane, while double shear has two. Two equal planes share the load and reduce average stress by half.
Why does N per mm² equal MPa?
A pascal is one newton per square metre. Converting the area scale shows that one newton per square millimetre equals one million pascals, or one megapascal.
How do I find a round pin's shear area?
Use the circular area pi times diameter squared divided by four. Enter the area of one cross section even when selecting double shear.
Is average shear stress the maximum stress?
Not necessarily, because real geometry and load transfer can create local peaks. Detailed design should account for stress concentrations, bending, bearing, and applicable code rules.