Newton's Law of Cooling Calculator
Predict an object's temperature over time from its initial temperature, surroundings, and cooling constant.
About Newton's Law of Cooling
Cooling Law Examples
| Initial Conditions | Final Temperature | Scenario |
|---|---|---|
| T0 = 100°C, Ta = 20°C, k = 0.1/min, t = 10 min | 49.430355°C | A hot object cooling toward room temperature. |
| T0 = 0°C, Ta = 20°C, k = 0.2/min, t = 5 min | 12.642411°C | A cold object warming in a room. |
| T0 = 80°C, Ta = 25°C, k = 0.05/min, t = 20 min | 45.233369°C | Slower cooling with the same exponential fraction remaining. |
How to Use the Cooling Calculator
- Enter the object's temperature at the start of the observation.
- Enter the constant ambient temperature surrounding the object.
- Provide the empirically determined cooling constant per minute.
- Enter elapsed time in minutes and select Calculate Temperature.
Newton's Cooling Law FAQ
Can the law model warming as well as cooling?
Yes. When initial temperature is below ambient temperature, the same equation predicts exponential warming toward the surroundings.
What are the units of the cooling constant?
The constant has inverse-time units. A per-minute constant must be paired with minutes, as it is in this calculator.
How can I determine the cooling constant?
Measure temperature at a known elapsed time under stable ambient conditions, then rearrange the exponential equation. Multiple measurements and curve fitting usually produce a more reliable estimate.
Does the object ever reach ambient temperature exactly?
The ideal exponential model approaches ambient temperature asymptotically. In practical measurement, the difference eventually becomes too small to distinguish.
When does Newton's law of cooling fail?
It becomes inaccurate with major internal temperature gradients, phase changes, varying surroundings, or changing heat-transfer conditions. Those situations require a spatial or time-varying thermal model.