Natural Frequency Calculator
Calculate natural frequency, period, and angular frequency for spring-mass systems and simple pendulums.
About Natural Frequency
Natural Frequency Examples
| System and Inputs | Calculated Response | Interpretation |
|---|---|---|
| Spring: m = 2 kg, k = 200 N/m | f = 1.591549 Hz, T = 0.628319 s | A compact laboratory oscillator. |
| Spring: m = 5 kg, k = 500 N/m | f = 1.591549 Hz, T = 0.628319 s | The same stiffness-to-mass ratio gives the same response. |
| Pendulum: L = 1 m, g = 9.81 m/s² | f = 0.498488 Hz, T = 2.006067 s | A classic seconds-pendulum scale. |
How to Calculate Natural Frequency
- Choose whether the oscillator is a spring-mass system or a simple pendulum.
- Enter the mass and spring constant, or the pendulum length and local gravity.
- Confirm that all values use the SI units shown beside their labels.
- Select Calculate Natural Frequency and review frequency, period, and angular frequency.
Natural Frequency FAQ
What is natural frequency?
Natural frequency is the rate of free oscillation after a system is disturbed. It is set by physical properties such as stiffness, mass, length, and gravity.
How are frequency and period related?
Period is the time for one complete cycle, while frequency is the number of cycles per second. They are reciprocals, so T equals 1 divided by f.
Does damping change natural frequency?
Damping slightly lowers the observed damped natural frequency relative to the undamped value calculated here. The difference is small for lightly damped systems but can matter when damping is strong.
Why does pendulum mass not affect the result?
Both the gravitational restoring force and inertia are proportional to pendulum mass. The mass terms cancel in the ideal small-angle equation.
When is the pendulum formula inaccurate?
The formula assumes small angular displacement and a massless rigid cord. Large amplitudes, flexible supports, air drag, and distributed bob geometry require corrections.