Natural Frequency Calculator

Calculate natural frequency, period, and angular frequency for spring-mass systems and simple pendulums.

Oscillation Calculator
Choose a system, enter its physical properties, and calculate its undamped natural response.

About Natural Frequency

Natural frequency is the rate at which a system tends to oscillate after it is displaced and released without a continuing external force. Every elastic mechanical system has one or more natural frequencies determined by its mass distribution, stiffness, geometry, and boundary conditions. This calculator covers two foundational models: an ideal spring carrying a concentrated mass and a simple pendulum making small swings. These models are useful starting points for physics lessons, vibration analysis, machine design, and preliminary engineering estimates. For a spring-mass system, angular natural frequency equals the square root of spring stiffness divided by mass. Frequency in hertz is angular frequency divided by two pi, while the period is the reciprocal of frequency. Increasing stiffness raises the frequency because the restoring force becomes stronger. Increasing mass lowers the frequency because greater inertia resists changes in motion. The ideal equation assumes a linear spring, a rigid supporting structure, negligible damping, and a mass that can be represented by one concentrated value. For a simple pendulum, angular frequency equals the square root of gravitational acceleration divided by pendulum length. A longer pendulum therefore swings more slowly, while stronger gravity produces faster oscillation. Mass does not appear because gravitational force and inertia scale together and cancel. The familiar pendulum equation is a small-angle approximation; it is highly accurate for modest amplitudes but increasingly underestimates the period for large swings. Natural frequency should not be confused with forcing frequency. When a periodic input approaches a lightly damped system's natural frequency, resonance can amplify motion substantially. Real systems include damping, distributed mass, flexible supports, nonlinear materials, and multiple vibration modes, so measured values may differ from an ideal calculation. Use the result to understand trends, check hand calculations, or establish an initial design target. Safety-critical structures and rotating machinery require a detailed modal analysis and experimental validation.

Natural Frequency Examples

System and InputsCalculated ResponseInterpretation
Spring: m = 2 kg, k = 200 N/mf = 1.591549 Hz, T = 0.628319 sA compact laboratory oscillator.
Spring: m = 5 kg, k = 500 N/mf = 1.591549 Hz, T = 0.628319 sThe same stiffness-to-mass ratio gives the same response.
Pendulum: L = 1 m, g = 9.81 m/s²f = 0.498488 Hz, T = 2.006067 sA classic seconds-pendulum scale.

How to Calculate Natural Frequency

  1. Choose whether the oscillator is a spring-mass system or a simple pendulum.
  2. Enter the mass and spring constant, or the pendulum length and local gravity.
  3. Confirm that all values use the SI units shown beside their labels.
  4. Select Calculate Natural Frequency and review frequency, period, and angular frequency.

Natural Frequency FAQ

What is natural frequency?

Natural frequency is the rate of free oscillation after a system is disturbed. It is set by physical properties such as stiffness, mass, length, and gravity.

How are frequency and period related?

Period is the time for one complete cycle, while frequency is the number of cycles per second. They are reciprocals, so T equals 1 divided by f.

Does damping change natural frequency?

Damping slightly lowers the observed damped natural frequency relative to the undamped value calculated here. The difference is small for lightly damped systems but can matter when damping is strong.

Why does pendulum mass not affect the result?

Both the gravitational restoring force and inertia are proportional to pendulum mass. The mass terms cancel in the ideal small-angle equation.

When is the pendulum formula inaccurate?

The formula assumes small angular displacement and a massless rigid cord. Large amplitudes, flexible supports, air drag, and distributed bob geometry require corrections.