Hydraulic Jump Calculator

Analyze conjugate depths, Froude numbers, downstream velocity, and energy dissipation in rectangular open-channel flow.

Hydraulic jump inputs
Enter upstream depth and velocity with the applicable gravitational acceleration.

About hydraulic jumps

A hydraulic jump is a rapid transition from shallow, fast, supercritical open-channel flow to deeper, slower, subcritical flow. The water surface rises abruptly, intense turbulence develops, and part of the flow's mechanical energy becomes heat, sound, and small-scale motion. Jumps are familiar downstream of spillways, sluice gates, and steep channels. Engineers often create them deliberately in stilling basins because controlled energy dissipation protects downstream beds and structures from erosion. The Froude number identifies the flow regime by comparing inertial effects with gravity-wave effects. It equals mean velocity divided by the square root of gravitational acceleration times hydraulic depth. For a wide rectangular channel, hydraulic depth is the water depth. A Froude number above one is supercritical, a value below one is subcritical, and one is critical. A classical hydraulic jump requires an upstream Froude number greater than one. If the entered value is at or below one, the conjugate-depth equation still produces a numerical result, but it does not describe a normal energy-dissipating jump. This calculator applies the momentum relationship for a horizontal, rectangular channel. The downstream conjugate depth equals one half of the upstream depth multiplied by the square root of one plus eight times the upstream Froude number squared, minus one. Continuity then gives downstream velocity from the ratio of upstream to downstream depth. The downstream Froude number is evaluated from that new depth and velocity. The specific energy dissipated across the ideal jump equals the cube of the depth difference divided by four times the product of the two depths. The equations assume steady flow, hydrostatic pressure away from the roller, uniform velocity across each section, negligible bed slope over the jump, and no important lateral contraction. Real jumps are three-dimensional and their length is several times the downstream depth. Tailwater conditions determine whether a jump forms at the expected location, becomes submerged, or sweeps downstream. Use these results as preliminary hydraulic values and pair them with stilling-basin guidance, freeboard checks, sediment considerations, and physical or numerical modeling for consequential designs. Units must be consistent; the provided defaults and labels use metres and seconds.

Hydraulic jump examples

Upstream conditionsIdeal resultsInterpretation
Depth 1 m; velocity 6.264 m/sFr₁ 2; downstream depth 2.372 mA distinct supercritical-to-subcritical jump.
Depth 0.5 m; velocity 4.429 m/sFr₁ 2; downstream depth 1.186 mGeometrically similar at half scale.
Depth 0.8 m; velocity 8 m/sFr₁ 2.856; downstream depth 2.856 mA stronger jump with greater dissipation.

How to calculate a hydraulic jump

  1. Measure or estimate the water depth immediately upstream of the jump.
  2. Enter the section-average upstream velocity and confirm local gravity.
  3. Select Calculate Hydraulic Jump to compute the conjugate downstream condition.
  4. Check that the upstream Froude number exceeds one and compare the downstream depth with available tailwater.

Frequently asked questions

When does a hydraulic jump occur?

It occurs when supercritical flow is forced to become subcritical, usually by downstream depth control. The transition creates a turbulent roller and an abrupt rise in water surface.

What is conjugate depth?

Conjugate depths are the upstream and downstream depths that have equal momentum function for the assumed channel. They bracket an ideal hydraulic jump but do not have equal specific energy.

Why is energy lost through the jump?

Large eddies, air entrainment, and turbulence convert organized flow energy into heat and motion at smaller scales. Momentum is approximately conserved while mechanical energy is not.

Does channel width affect the result?

For the wide rectangular equations used here, width cancels when velocity and depth are known. Width is still needed to convert between velocity and total discharge.

Can I use this for a trapezoidal channel?

Not directly, because the conjugate-depth relationship here assumes a rectangular cross section. Irregular and trapezoidal channels require momentum functions based on their actual geometry.