Evaporation Rate Calculator

Estimate open-water evaporation from temperature, relative humidity, wind speed, and exposed surface area.

Estimate water evaporation
This screening model combines saturation vapor pressure, vapor deficit, wind, and area.

About evaporation rate estimates

Evaporation transfers liquid water into the atmosphere when energetic surface molecules escape as vapor. Its rate depends on the difference between the vapor pressure at the water surface and the vapor already present in the surrounding air. Warm water has a higher saturation vapor pressure, dry air produces a larger vapor pressure deficit, and moving air replaces the moist boundary layer above the surface. A larger exposed area supplies proportionally more surface from which evaporation can occur. This calculator first estimates saturation vapor pressure with the widely used Magnus relationship: 0.6108 times exp(17.27T divided by T plus 237.3), where T is water temperature in degrees Celsius and pressure is in kilopascals. It multiplies that pressure by one minus relative humidity as a decimal to obtain vapor pressure deficit. The screening rate is then 0.1 times surface area times vapor pressure deficit times a wind factor of one plus 0.5 times wind speed. Under this model one kilogram of water is approximately one liter of volume lost. The calculation is intentionally an estimate rather than a site-specific engineering guarantee. Actual evaporation is influenced by solar radiation, air temperature, atmospheric pressure, water chemistry, turbulence, pool occupancy, covers, shading, heat supplied to the water, and the geometry of surrounding structures. Indoor pools also depend strongly on ventilation and whether the air near the water is already saturated. Natural lakes may store heat and experience varying wind over a long fetch, so daily weather data and calibrated hydrological models are preferable for water-balance studies. Use water temperature rather than air temperature when it is known, because saturation conditions are established at the liquid surface. Relative humidity must be between zero and one hundred percent. Wind speed should represent conditions just above the water; values from a distant weather station may not describe a sheltered pool or tank. Surface area is the horizontal water area, not the wetted wall area. The hourly result can be multiplied by twenty-four for a constant-condition daily estimate, as displayed here. This tool is useful for comparing scenarios, estimating makeup-water demand, exploring how covers reduce exposed area, and checking the order of magnitude of water loss. For equipment sizing, regulated facilities, irrigation scheduling, or environmental permits, use a method approved for the application and local climate. Measurements over several representative days can be used to calibrate the model coefficient and improve predictions for a particular site.

Evaporation rate examples

The examples show how warmer, drier, and windier conditions increase estimated loss.

ConditionsEstimated rateContext
25°C, 50% RH, 2 m/s, 10 m²3.168 kg/hWarm outdoor pool with a moderate breeze.
20°C, 60% RH, 1 m/s, 5 m²0.701 kg/hSmaller, milder, partly sheltered surface.
30°C, 40% RH, 3 m/s, 20 m²12.729 kg/hHot, dry, windy conditions over a larger area.

How to estimate evaporation

  1. Enter the water surface temperature in degrees Celsius.
  2. Enter relative humidity from zero to one hundred percent and the local wind speed in meters per second.
  3. Enter the exposed horizontal water surface area in square meters.
  4. Select Calculate Evaporation Rate and review the hourly and daily screening estimates.

Evaporation rate FAQ

Is one kilogram per hour equal to one liter per hour?

For ordinary water, one kilogram is approximately one liter. The small density change with temperature is normally insignificant for this screening estimate.

Why does wind increase evaporation?

Wind removes the humid boundary layer that develops immediately above the water. Replacing it with drier ambient air maintains a larger vapor pressure gradient.

What happens at 100 percent relative humidity?

This simplified equation produces zero net evaporation because its vapor pressure deficit becomes zero. Real local conditions may still permit condensation or evaporation if air and water temperatures differ.

Can I use air temperature instead of water temperature?

Water temperature is preferred because it controls saturation vapor pressure at the surface. Air temperature can be a rough proxy only when the water is close to thermal equilibrium with the air.

Is this suitable for final pool HVAC design?

No, final design should follow applicable engineering standards and account for occupancy, ventilation, activity, and heat input. This result is best for comparisons and preliminary estimates.