Coefficient of Performance Calculator

Calculate COP for heat pumps, air conditioners, and refrigeration systems.

Coefficient of performance calculation
Enter useful thermal output and energy input in the same energy unit.

About coefficient of performance

Coefficient of performance measures how effectively a heating or cooling system moves thermal energy compared with the energy it consumes. It is calculated as useful thermal output divided by work or electrical energy input. For a heat pump in heating mode, useful output is heat delivered indoors. For a refrigerator or air conditioner, useful output is heat removed from the cooled space. Because these devices move heat rather than converting all input energy directly into heat, COP can legitimately be greater than one. The equation is COP = useful energy output ÷ energy input. Both quantities must cover the same time period and use the same energy unit. Kilowatt-hours, British thermal units, and joules all produce the same dimensionless ratio when used consistently. A heat pump that delivers 12.6 kWh of heat while consuming 3.5 kWh of electricity has a COP of 3.6. That means it moves 3.6 units of useful heat for every unit of purchased energy. COP depends strongly on operating conditions. A heat pump generally performs better when the temperature difference between its source and destination is small. Cold outdoor air, high supply-water temperatures, frost, dirty coils, poor airflow, compressor cycling, and auxiliary resistance heat can reduce real performance. Refrigeration COP likewise varies with evaporating and condensing temperatures, equipment loading, and maintenance. A manufacturer's rated value applies only at specified test conditions. The percentage shown by this calculator is simply COP multiplied by 100 and is best described as an output-to-input ratio, not conventional conversion efficiency. Calling a COP of 3.6 a 360 percent efficiency can be misleading because energy is conserved: the additional heat comes from the surrounding environment. For meaningful comparisons, use measured energy totals over matching boundaries and time intervals. Do not mix cooling capacity in kilowatts with electrical consumption in kilowatt-hours without accounting for operating time. Seasonal metrics such as SCOP, HSPF, SEER, or measured annual COP are often more representative than a single operating-point result.

Example Calculations

Energy valuesCOPSystem
12.6 kWh output, 3.5 kWh input3.6Residential heat pump
8.4 kWh output, 2.4 kWh input3.5Air conditioner
25.2 kWh output, 4.2 kWh input6.0Commercial refrigerator
126 kWh output, 28 kWh input4.5Industrial heat pump

How to use the calculator

  1. Enter the useful heating or cooling energy delivered.
  2. Enter the energy consumed over the same interval.
  3. Choose the common energy unit used for both values.
  4. Select Calculate COP and compare the result under like operating conditions.

Frequently asked questions

Can COP be greater than one?

Yes, because a heat pump or refrigerator moves heat from one place to another. Input work is not the only energy appearing at the useful side of the system.

What is a good heat pump COP?

A higher COP indicates more useful heat per unit of input at the stated conditions. Typical values vary substantially with climate, temperatures, equipment, and operating point.

Why must both inputs use the same unit?

COP is a ratio and the energy units must cancel. Mixing units without conversion changes the numerical result and makes it meaningless.

Is COP the same as efficiency?

Not exactly, because conventional efficiency compares converted output with input and normally remains at or below one. COP describes transported thermal energy and can exceed one.

Does rated COP equal seasonal performance?

No, rated COP usually describes a specific laboratory condition. Seasonal performance includes changing weather, cycling, defrost operation, and auxiliary energy.