Electrolysis Calculator

Apply Faraday's law to calculate deposited mass, electric charge, current, or electrolysis time.

Faraday's law calculator
Choose the unknown quantity and enter the electrochemical data.

About the electrolysis calculator

Electrolysis uses electrical energy to drive a chemical change that would not otherwise occur spontaneously. During the process, electrons move through an external circuit while ions move through an electrolyte. Faraday's law connects that electron flow to the amount of material oxidized or reduced at an electrode. This calculator turns the law into a practical solver for deposited mass, total charge, current, or elapsed time. The core relationship is mass equals charge multiplied by molar mass, divided by the number of electrons and Faraday's constant. Charge itself equals current multiplied by time. The calculator uses 96,485.33212 coulombs per mole of electrons for Faraday's constant. Molar mass must be entered in grams per mole, current in amperes, time in seconds, and deposited or consumed mass in grams. The electron count comes from the balanced half-reaction. Copper ions reduced from Cu2+ require two electrons, while silver ions reduced from Ag+ require one. To find mass, provide current, time, molar mass, and electrons transferred. To find charge, provide measured mass and the chemical quantities. Current and time modes rearrange the same equation, so all four results remain internally consistent. The ideal calculation assumes one hundred percent current efficiency: every electron contributes to the intended electrode reaction. Real cells can also support gas evolution, side reactions, leakage, or incomplete recovery, making measured yield lower than the theoretical result. Unit consistency is essential. One ampere is one coulomb per second, which is why time must be converted from minutes or hours before entry. The molar mass belongs to the substance formed or consumed, not necessarily the complete electrolyte formula. The number of electrons is a stoichiometric coefficient from the balanced reaction, not the ion charge written without its sign. Electroplating, metal refining, battery research, chlorine production, and laboratory coulometry all rely on these relationships. Students can use the calculator to verify dimensional analysis and balanced half-reactions, while technicians can estimate production rates or required run times. For engineering specifications, correct the theoretical answer for current efficiency, electrode area, transport limitations, and process-specific operating conditions.

Electrolysis examples

Known valuesResultExplanation
2 A, 3600 s, Cu 63.546 g/mol, 2 electrons2.3709 g CuTwo amperes for one hour deposits the theoretical copper mass.
1 A, 965.853 s, Ag 107.8682 g/mol, 1 electron1.0798 g AgSilver needs one electron per atom, so its equivalent mass is high.
5 g Cu, 63.546 g/mol, 2 electrons15,183 CCharge is found by rearranging Faraday's mass equation.

How to use the electrolysis calculator

  1. Choose whether to calculate mass, charge, current, or time.
  2. Enter the molar mass of the electrode product and electrons transferred in its half-reaction.
  3. Provide the remaining electrical or mass measurements in the displayed units.
  4. Select Calculate and read the theoretical result.

Electrolysis calculator FAQ

What value does the calculator use for Faraday's constant?

It uses 96,485.33212 coulombs per mole of electrons. This accepted value gives ample precision for classroom and practical calculations.

How do I determine the number of electrons?

Balance the oxidation or reduction half-reaction and read its electron coefficient. For example, reducing Cu2+ to copper metal consumes two electrons per copper ion.

Why is actual deposited mass lower than the result?

The result assumes perfect current efficiency and complete recovery. Side reactions, gas formation, and physical losses can reduce the measured mass.

Can I enter time in hours?

Convert hours to seconds by multiplying by 3,600 before entering the value. This keeps current in amperes consistent with charge in coulombs.

Does electrode area affect Faraday's law?

Area does not appear in the ideal total-mass equation. It affects current density, surface quality, transport, and therefore real process efficiency.